← all posts

Surface area and volume of a sphere in finite Euclidean space

2025-04-06·10 min read·

A derivation of the volume of the Euclidean unit ball and the surface area of the unit sphere via spherical coordinates, induced metrics, and the Gaussian integral.

Motivation

The computation of the area and volume of a sphere is one of the classical problems of geometry. In dimension two, the corresponding formulas are already familiar:

Length⁡(∂B2(0,r))=2πr,Area⁡(B2(0,r))=πr2.\operatorname{Length}(\partial B^2(0,r)) = 2\pi r, \qquad \operatorname{Area}(B^2(0,r)) = \pi r^2.

In dimension three, the standard formulas are

Area⁡(Sr2)=4πr2,Vol⁡(B3(0,r))=43πr3.\operatorname{Area}(\mathbb{S}^2_r)=4\pi r^2, \qquad \operatorname{Vol}(B^3(0,r))=\frac{4}{3}\pi r^3.

Historically, the three-dimensional case goes back to Archimedes. In "On the Sphere and Cylinder", Archimedes established the relation between a sphere and its circumscribed cylinder: the volume of the sphere is two-thirds the volume of the circumscribed cylinder, and the surface area of the sphere is equal to the lateral area of that cylinder.

Thus, in low dimensions, the formulas look elementary and geometric. However, once we pass from R2\mathbb{R}^2 and R3\mathbb{R}^3 to arbitrary Rn\mathbb{R}^n, the pattern is no longer obvious. One might expect powers of π\pi, but the exact dependence on nn is more subtle. The answer involves the Gamma function:

Vol⁡(Bn)=πn/2Γ(n/2+1),Area⁡(Sn−1)=2πn/2Γ(n/2).\operatorname{Vol}(B^n) = \frac{\pi^{n/2}}{\Gamma(n/2+1)}, \qquad \operatorname{Area}(\mathbb{S}^{n-1}) = \frac{2\pi^{n/2}}{\Gamma(n/2)}.

This already suggests that the general nn-dimensional problem is not merely a problem of elementary geometry, it belongs more naturally to analysis. The Gamma function itself arose from the problem of extending the factorial beyond integer values. This problem appeared already in the work of Wallis on quadrature, and was developed much further in the 18th century by Euler and Stirling. Euler's work on the so-called Eulerian integrals made it possible to treat expressions such as

Γ(s)=∫0∞ts−1e−t dt\Gamma(s)=\int_0^\infty t^{s-1}e^{-t}\,dt

as a continuous analogue of the factorial.

There is also a natural connection with the theory of multiple integrals. In the nineteenth century, Dirichlet studied methods for determining multiple integrals, and this analytic tradition is exactly the setting in which the volume of an nn-dimensional ball becomes a clean calculation. Instead of trying to visualize a high-dimensional sphere, one evaluates an integral in two different ways: first by Fubini's theorem, and then by changing to spherical coordinates.

The key example is the Gaussian integral

∫Rne−∥x∥2 dx.\int_{\mathbb{R}^n} e^{-\|x\|^2}\,dx.

On the one hand, Fubini's theorem reduces it to the one-dimensional Gaussian integral:

∫Rne−∥x∥2 dx=(∫−∞∞e−x2 dx)n=πn/2.\int_{\mathbb{R}^n} e^{-\|x\|^2}\,dx = \left(\int_{-\infty}^{\infty}e^{-x^2}\,dx\right)^n = \pi^{n/2}.

On the other hand, spherical coordinates express the same integral as

∫Rne−∥x∥2 dx=∫0∞∫Sn−1e−r2rn−1 dσ dr.\int_{\mathbb{R}^n} e^{-\|x\|^2}\,dx = \int_0^\infty \int_{\mathbb{S}^{n-1}} e^{-r^2} r^{n-1}\,d\sigma\,dr.

The radial part then becomes a Gamma integral. Comparing the two evaluations reveals the surface area of the unit sphere, and integrating once more in the radial variable gives the volume of the unit ball.

Therefore, the goal of this article is to derive the formulas

An−1=Area⁡(Sn−1)=2πn/2Γ(n/2)A_{n-1} = \operatorname{Area}(\mathbb{S}^{n-1}) = \frac{2\pi^{n/2}}{\Gamma(n/2)}

and

Vn=Vol⁡(Bn)=πn/2Γ(n/2+1)V_n = \operatorname{Vol}(B^n) = \frac{\pi^{n/2}}{\Gamma(n/2+1)}

Conventions

Throughout this article, we denote

Bn=B(0,1)={x∈Rn∣∥x∥<1}andSn−1={x∈Rn∣∥x∥=1}.B^n = B(0,1) = \{x \in \mathbb{R}^n \mid \|x\| < 1\} \quad \text{and} \quad \mathbb{S}^{n-1} = \{x \in \mathbb{R}^n \mid \|x\| = 1\}.

The volume of the unit ball is defined by the ordinary coordinate integral

Vn=Vol⁡(Bn)=∫Bndx1⋯dxn.V_n = \operatorname{Vol}(B^n) = \int_{B^n} dx_1\cdots dx_n.

And the surface area of the unit sphere is defined by integrating the induced area element

An−1=Area⁡(Sn−1)=∫Sn−1dσ.A_{n-1} = \operatorname{Area}(\mathbb{S}^{n-1}) = \int_{\mathbb{S}^{n-1}} d\sigma.

The goal is to compute VnV_n and An−1A_{n-1} explicitly.


Necessary Tools

Two elementary analytic tools are used repeatedly.

Lemma (Gaussian Integral)
∫−∞∞e−x2 dx=π.\int_{-\infty}^\infty e^{-x^2}\,dx = \sqrt{\pi}.
Proof.

Let I=∫−∞∞e−x2 dxI=\int_{-\infty}^{\infty}e^{-x^2}\,dx. Since e−x2>0e^{-x^2}>0, I>0I>0. Then

I2=(∫−∞∞e−x2 dx)(∫−∞∞e−y2 dy)=∫R2e−(x2+y2) dx dy.I^2 = \left(\int_{-\infty}^\infty e^{-x^2}\,dx\right)\left(\int_{-\infty}^\infty e^{-y^2}\,dy\right) = \int_{\mathbb{R}^2} e^{-(x^2+y^2)}\,dx\,dy.

Use polar coordinates x=rcos⁡θx=r\cos\theta, y=rsin⁡θy=r\sin\theta, whose Jacobian is rr:

I2=∫02π∫0∞e−r2 r dr dθ=2π∫0∞re−r2 dr.I^2 = \int_0^{2\pi}\int_0^\infty e^{-r^2}\,r\,dr\,d\theta = 2\pi\int_0^\infty r e^{-r^2}\,dr.

With t=r2t=r^2 and dt=2r drdt=2r\,dr,

I2=2π⋅12∫0∞e−t dt=π⋅[−e−t]0∞=π.I^2 = 2\pi \cdot \frac{1}{2}\int_0^\infty e^{-t}\,dt = \pi\cdot\bigl[-e^{-t}\bigr]_0^\infty = \pi.

Since I>0I>0, I=πI=\sqrt{\pi}.

■
Lemma (Properties of the Gamma Function)

For s>0s > 0, the Gamma function defined by

Γ(s)=∫0∞ts−1e−t dt.\Gamma(s) = \int_0^\infty t^{s-1} e^{-t}\,dt.

satisfies the following properties:

  1. Γ(1)=1\Gamma(1) = 1.
  2. Γ(s+1)=s Γ(s)\Gamma(s+1) = s\,\Gamma(s) for all s>0s > 0.
  3. Consequently, for n∈Nn \in \mathbb{N}, Γ(n)=(n−1)!\Gamma(n) = (n-1)!
  4. Γ ⁣(12)=π\Gamma\!\left(\tfrac{1}{2}\right) = \sqrt{\pi}.
Proof.

1. Direct computation: Γ(1)=∫0∞e−t dt=[−e−t]0∞=1\Gamma(1) = \int_0^\infty e^{-t}\,dt = \bigl[-e^{-t}\bigr]_0^\infty = 1.

2. Integration by parts with u=tsu = t^s and dv=e−t dtdv = e^{-t}\,dt:

Γ(s+1)=∫0∞tse−t dt=[−tse−t]0∞+s∫0∞ts−1e−t dt.\Gamma(s+1) = \int_0^\infty t^s e^{-t}\,dt = \bigl[-t^s e^{-t}\bigr]_0^\infty + s\int_0^\infty t^{s-1}e^{-t}\,dt.

The boundary term vanishes since tse−t→0t^s e^{-t} \to 0 as t→0+t \to 0^+ and t→∞t \to \infty. Therefore Γ(s+1)=s Γ(s)\Gamma(s+1) = s\,\Gamma(s).

3. From 1 and 2, induction gives Γ(n+1)=n!\Gamma(n+1) = n!, i.e., Γ(n)=(n−1)!\Gamma(n) = (n-1)!.

4. Substituting t=x2t = x^2 in the definition,

Γ ⁣(12)=∫0∞t−1/2e−t dt=2∫0∞e−x2 dx=∫−∞∞e−x2 dx=π.\Gamma\!\left(\tfrac{1}{2}\right) = \int_0^\infty t^{-1/2} e^{-t}\,dt = 2\int_0^\infty e^{-x^2}\,dx = \int_{-\infty}^\infty e^{-x^2}\,dx = \sqrt{\pi}.
■

Computing VnV_n

We will start by changing variables into polar coordinates. Consider the equation x12+⋯+xn2=1x_1^2+\cdots+x_n^2=1. Since −1≤x1≤1-1\le x_1\le 1, write x1=cos⁡θ1x_1=\cos\theta_1. Then x22+⋯+xn2=sin⁡2θ1x_2^2+\cdots+x_n^2=\sin^2\theta_1. Next write x2=sin⁡θ1cos⁡θ2x_2=\sin\theta_1\cos\theta_2, so x32+⋯+xn2=sin⁡2θ1sin⁡2θ2x_3^2+\cdots+x_n^2=\sin^2\theta_1\sin^2\theta_2. Iterating this substitution gives

{x1=cos⁡θ1x2=sin⁡θ1cos⁡θ2⋮xn−1=sin⁡θ1⋯sin⁡θn−2cos⁡θn−1xn=sin⁡θ1⋯sin⁡θn−2sin⁡θn−1θ1,…,θn−2∈[0,π),θn−1∈[0,2π).\begin{cases} x_1 = \cos\theta_1 \\ x_2 = \sin\theta_1\cos\theta_2 \\ \quad\vdots \\ x_{n-1} = \sin\theta_1\cdots\sin\theta_{n-2}\cos\theta_{n-1} \\ x_n = \sin\theta_1\cdots\sin\theta_{n-2}\sin\theta_{n-1} \end{cases} \quad \theta_1,\dots,\theta_{n-2} \in [0,\pi),\quad \theta_{n-1} \in [0,2\pi).

Define σ(θ1,…,θn−1)=(x1,…,xn)\sigma(\theta_1,\dots,\theta_{n-1})=(x_1,\dots,x_n). Points away from the origin are written as x=rσx=r\sigma. The Jacobian of (r,θ)↦rσ(θ)(r,\theta)\mapsto r\sigma(\theta) is

J(rσ)(r,θ1,…,θn−1)=det⁡(∂x∂r,  ∂x∂θ1,  …,  ∂x∂θn−1)=rn−1det⁡(σ,  ∂σ∂θ1,  …,  ∂σ∂θn−1).J(r\sigma)(r,\theta_1,\dots,\theta_{n-1}) = \det\begin{pmatrix}\dfrac{\partial x}{\partial r},\; \dfrac{\partial x}{\partial\theta_1},\;\dots,\; \dfrac{\partial x}{\partial\theta_{n-1}}\end{pmatrix} = r^{n-1}\det\begin{pmatrix}\sigma,\; \dfrac{\partial\sigma}{\partial\theta_1},\;\dots,\; \dfrac{\partial\sigma}{\partial\theta_{n-1}}\end{pmatrix}.

The remaining determinant is evaluated through its Gram matrix. Set

A=(σ,∂σ∂θ1,…,∂σ∂θn−1).A=\left(\sigma,\frac{\partial\sigma}{\partial\theta_1},\dots,\frac{\partial\sigma}{\partial\theta_{n-1}}\right).

Then ∣det⁡A∣2=det⁡(ATA)|\det A|^2=\det(A^TA).

Induced Metric and Area Element

The geometric origin of the induced metric is classical. For a surface parametrized by X(u,v)⊆R3X(u,v)\subseteq \mathbb{R}^3, Gauss studied the quadratic expression

ds2=E du2+2F du dv+G dv2,ds^2 = E\,du^2+2F\,du\,dv+G\,dv^2,

where

E=⟨Xu,Xu⟩,F=⟨Xu,Xv⟩,G=⟨Xv,Xv⟩.E=\langle X_u,X_u\rangle,\qquad F=\langle X_u,X_v\rangle,\qquad G=\langle X_v,X_v\rangle.

This is the first fundamental form of the surface. In modern language, it is the metric induced on the surface by the Euclidean inner product of the ambient space. Thus the basic idea of an induced metric goes back to Gauss's theory of surfaces.

Riemann later abstracted this idea. Instead of studying only surfaces embedded in Euclidean space, he considered nn-dimensional manifolds equipped with an intrinsic line element. This is the origin of Riemannian geometry: a manifold is given a smoothly varying inner product on its tangent spaces, and geometric quantities such as length, angle, area, and volume are derived from this metric.

Theorem (Riemannian Volume Form)

Let (Σm,g)(\Sigma^m,g) be an oriented Riemannian manifold. In any positively oriented smooth coordinates (xi)(x^i),

ωg=det⁡(gij) dx1∧⋯∧dxm.\omega_g = \sqrt{\det(g_{ij})}\,dx^1\wedge\cdots\wedge dx^m.
Proof.

Recall that in local coordinates (xi)(x^i),

dxi1∧⋯∧dxik(∂xj1,…,∂xjk)=δj1⋯jki1⋯ikdx^{i_1}\wedge\cdots\wedge dx^{i_k} (\partial_{x^{j_1}},\ldots,\partial_{x^{j_k}}) = \delta^{i_1\cdots i_k}_{j_1\cdots j_k}

for all multi-indices I=(i1,…,ik)I=(i_1,\ldots,i_k) and J=(j1,…,jk)J=(j_1,\ldots,j_k).

In positively oriented smooth coordinates, write

ωg=f dx1∧⋯∧dxm.\omega_g = f\,dx^1\wedge\cdots\wedge dx^m.

Since (∂xi∣p)(\partial_{x^i}|_p) is a basis for TpΣT_p\Sigma, Gram-Schmidt gives a positively oriented local orthonormal frame (Ek)(E_k) and a transition matrix C=[Cik]C=[C_{ik}] such that

∂xi=∑k=1mCikEk.\partial_{x^i}=\sum_{k=1}^m C_{ik}E_k.

Let (εk)(\varepsilon^k) be the dual coframe of (Ek)(E_k), so εk(El)=δlk\varepsilon^k(E_l)=\delta^k_l. Since ωg\omega_g is multilinear and alternating, and ωg(E1,…,Em)=1\omega_g(E_1,\ldots,E_m)=1,

f=ωg(∂x1,…,∂xm)=det⁡(εk(∂xi))=det⁡(C).f =\omega_g(\partial_{x^1},\ldots,\partial_{x^m}) =\det\bigl(\varepsilon^k(\partial_{x^i})\bigr) =\det(C).

Moreover, since (Ek)(E_k) is orthonormal,

gij=⟨∂xi,∂xj⟩=⟨∑k=1mCikEk,∑l=1mCjlEl⟩=∑k=1m∑l=1mCikCjl⟨Ek,El⟩=∑k=1mCikCjk=(CCT)ij.\begin{aligned} g_{ij} &=\langle \partial_{x^i},\partial_{x^j}\rangle \\ &=\left\langle \sum_{k=1}^m C_{ik}E_k,\sum_{l=1}^m C_{jl}E_l\right\rangle \\ &=\sum_{k=1}^m\sum_{l=1}^m C_{ik}C_{jl}\langle E_k,E_l\rangle \\ &=\sum_{k=1}^m C_{ik}C_{jk} =(CC^T)_{ij}. \end{aligned}

Thus G=CCTG=CC^T, so

det⁡(G)=det⁡(CCT)=det⁡(C)2.\det(G)=\det(CC^T)=\det(C)^2.

Since both (∂xi)(\partial_{x^i}) and (Ek)(E_k) are positively oriented, det⁡(C)>0\det(C)>0. Hence f=det⁡(G)f=\sqrt{\det(G)}.

■

Historically, this formula belongs to the Riemannian tradition, since the metric determines infinitesimal volume. However, the modern expression as a top-degree differential form belongs to the language of differential forms, developed systematically by Cartan and later by de Rham. The area element used above comes from the Riemannian volume form of the metric induced on the hypersurface.

Let Mm,NnM^m,N^n be smooth manifolds and let gg be a Riemannian metric on NN. For a smooth map F:M→NF:M\to N, the pullback F∗gF^*g on MM defined by

(F∗g)p(X,Y):=gF(p)(dFp(X),dFp(Y)),X,Y∈TpM.(F^*g)_p(X,Y) :=g_{F(p)}(dF_p(X),dF_p(Y)), \qquad X,Y\in T_pM.

It's not hard to prove that F∗gF^*g is also a Riemannian metric on MM.

Let Σ⊆M\Sigma\subseteq M be a Riemannian submanifold with the metric induced from (Mm+1,g)(M^{m+1},g), and let F:U⊆Rm→ΣF:U\subseteq\mathbb{R}^m\to\Sigma be a local parametrization. For the coordinate frame (∂xi)(\partial_{x^i}) on UU,

(F∗g)p(∂xi,∂xj)=gF(p)(dFp(∂xi),dFp(∂xj))=gF(p)(∂xiF,∂xjF).(F^*g)_p(\partial_{x^i},\partial_{x^j}) =g_{F(p)}(dF_p(\partial_{x^i}),dF_p(\partial_{x^j})) =g_{F(p)}(\partial_{x^i}F,\partial_{x^j}F).

Therefore, if G=[(F∗g)ij]G=[(F^*g)_{ij}], the hypersurface area is computed locally by

A(Σ)=∫Σωg=∫F−1(Σ)det⁡(G) dx1⋯dxm.\mathcal{A}(\Sigma) =\int_{\Sigma}\omega_g =\int_{F^{-1}(\Sigma)}\sqrt{\det(G)}\,dx^1\cdots dx^m.

The ambient metric in the present computation is Euclidean, g=∑i,jδij dxi⊗dxjg=\sum_{i,j}\delta_{ij}\,dx^i\otimes dx^j. For the parametrization σ\sigma of Sn−1\mathbb{S}^{n-1}, the induced metric matrix is

gij=⟨∂σ∂θi, ∂σ∂θj⟩,1≤i,j≤n−1.g_{ij} = \left\langle \frac{\partial\sigma}{\partial\theta_i},\, \frac{\partial\sigma}{\partial\theta_j}\right\rangle, \quad 1 \le i,j \le n-1.

This is the Gram matrix of the tangent vectors. Therefore the area element on the sphere is

dσ=∣det⁡G∣  dθ1⋯dθn−1.d\sigma = \sqrt{|\det G|}\; d\theta_1\cdots d\theta_{n-1}.

For the graph case, if F:U→ΣF:U\to\Sigma is given by

F(x1,…,xm)=(x1,…,xm,f(x1,…,xm)),F(x^1,\ldots,x^m)=(x^1,\ldots,x^m,f(x^1,\ldots,x^m)),

then writing fi=∂xiff_i=\partial_{x^i}f gives

g~ij=⟨∂xiF,∂xjF⟩=δij+fifj.\widetilde{g}_{ij} =\langle \partial_{x^i}F,\partial_{x^j}F\rangle =\delta_{ij}+f_if_j.

Equivalently,

G~=Im+∇fT∇f.\widetilde{G}=I_m+\nabla f^T\nabla f.

To compute the determinant, observe that every eigenvalue of G~\widetilde{G} has the form 1+λ1+\lambda, where λ\lambda is an eigenvalue of ∇fT∇f\nabla f^T\nabla f. If λ≠0\lambda\neq 0 and v∈Eλ(∇fT∇f)v\in E_\lambda(\nabla f^T\nabla f), then

(∇fT∇f)(v)=[f1⟨∇f,v⟩f2⟨∇f,v⟩⋮fm⟨∇f,v⟩]=λv.(\nabla f^T\nabla f)(v) =\begin{bmatrix} f_1\langle\nabla f,v\rangle\\ f_2\langle\nabla f,v\rangle\\ \vdots\\ f_m\langle\nabla f,v\rangle \end{bmatrix} =\lambda v.

Hence v=⟨∇f,v⟩λ∇fv=\frac{\langle\nabla f,v\rangle}{\lambda}\nabla f, so the nonzero eigenspace is spanned by ∇f\nabla f. Substituting v=∇fv=\nabla f gives

(∇fT∇f)(∇f)=∣∇f∣2∇f.(\nabla f^T\nabla f)(\nabla f)=|\nabla f|^2\nabla f.

Thus ∣∇f∣2|\nabla f|^2 is the unique nonzero eigenvalue. The zero eigenspace is (∇f)⊥(\nabla f)^\perp when ∇f≠0\nabla f\neq 0, and the conclusion is immediate when ∇f=0\nabla f=0. Therefore

spec⁡(∇fT∇f)={∣∇f∣2,0,…,0},\operatorname{spec}(\nabla f^T\nabla f)=\{|\nabla f|^2,0,\ldots,0\},

and so

det⁡(G~)=1+∣∇f∣2.\det(\widetilde{G})=1+|\nabla f|^2.

Thus the graph area formula is

A(Σ)=∫F−1(Σ)1+∣∇f∣2 dx1⋯dxm.\mathcal{A}(\Sigma) =\int_{F^{-1}(\Sigma)}\sqrt{1+|\nabla f|^2}\,dx^1\cdots dx^m.

Return to the sphere. Since ∣σ∣=1|\sigma|=1, ⟨σ,σ⟩=1\langle\sigma,\sigma\rangle=1. Differentiating with respect to θj\theta_j gives

⟨σ, ∂σ∂θj⟩=0,∀ 1≤j≤n−1.\left\langle\sigma,\, \frac{\partial\sigma}{\partial\theta_j}\right\rangle = 0, \quad \forall\, 1 \le j \le n-1.

Therefore

ATA=[100G]  ⟹  ∣det⁡A∣2=det⁡(ATA)=∣det⁡G∣,A^T A = \begin{bmatrix} 1 & 0 \\ 0 & G \end{bmatrix} \implies |\det A|^2 = \det(A^T A) = |\det G|,

so ∣det⁡A∣=∣det⁡G∣|\det A|=\sqrt{|\det G|}. Hence the Euclidean volume element in spherical coordinates is

dx=rn−1∣det⁡G∣  dr dθ1⋯dθn−1=rn−1 dr dσ.dx = r^{n-1}\sqrt{|\det G|}\; dr\,d\theta_1\cdots d\theta_{n-1} = r^{n-1}\,dr\,d\sigma.

Using the volume element above on the unit ball,

Vn=∫Bndx=∫01∫Sn−1rn−1 dσ dr=An−1∫01rn−1 dr=An−1n.V_n = \int_{B^n} dx = \int_0^1\int_{\mathbb{S}^{n-1}} r^{n-1}\,d\sigma\,dr = A_{n-1}\int_0^1 r^{n-1}\,dr = \frac{A_{n-1}}{n}.

Thus evaluation of VnV_n is reduced to evaluation of the surface area term An−1A_{n-1}.


Computing An−1A_{n-1}

To evaluate An−1A_{n-1}, use the nn-dimensional Gaussian integral

I=∫Rne−∥x∥2 dx.I = \int_{\mathbb{R}^n} e^{-\|x\|^2}\,dx.

Compute II in two ways.

Method 1 (Fubini).

∫Rne−∥x∥2 dx=∫Rne−(x12+⋯+xn2) dx1⋯dxn=(∫−∞∞e−x2 dx)n=πn/2.\int_{\mathbb{R}^n} e^{-\|x\|^2}\,dx = \int_{\mathbb{R}^n} e^{-(x_1^2+\cdots+x_n^2)}\,dx_1\cdots dx_n = \left(\int_{-\infty}^\infty e^{-x^2}\,dx\right)^n = \pi^{n/2}.

Method 2 (Spherical coordinates).

I=∫0∞∫Sn−1rn−1e−r2 dσ dr=An−1∫0∞rn−1e−r2 dr.I = \int_0^\infty\int_{\mathbb{S}^{n-1}} r^{n-1} e^{-r^2}\,d\sigma\,dr = A_{n-1}\int_0^\infty r^{n-1} e^{-r^2}\,dr.

With t=r2t=r^2 and dt=2r drdt=2r\,dr,

I=An−12∫0∞t(n−2)/2e−t dt=An−12 Γ(n/2).I = \frac{A_{n-1}}{2}\int_0^\infty t^{(n-2)/2} e^{-t}\,dt = \frac{A_{n-1}}{2}\,\Gamma(n/2).

Comparing both methods gives

An−1=2πn/2Γ(n/2).\boxed{A_{n-1} = \frac{2\pi^{n/2}}{\Gamma(n/2)}}.

Substituting this into Vn=An−1/nV_n=A_{n-1}/n gives

Vn=πn/2Γ(n/2+1).\boxed{V_n = \frac{\pi^{n/2}}{\Gamma(n/2+1)}}.

References

[1] G. B. Folland, Real Analysis: Modern Techniques and Their Applications, 2nd ed., John Wiley & Sons, New York, 1999.

[2] J. H. Hubbard and B. B. Hubbard, Vector Calculus, Linear Algebra, and Differential Forms: A Unified Approach, 5th ed., Matrix Editions, Ithaca, 2015.

[3] J. M. Lee, Introduction to Smooth Manifolds, 2nd ed., Grad. Texts in Math., vol. 218, Springer, New York, 2013.

[4] Archimedes, On the Sphere and Cylinder, in T. L. Heath (trans.), The Works of Archimedes, Cambridge University Press, 1897.

[5] R. Roy, “The Gamma Function,” in Sources in the Development of Mathematics, Cambridge University Press, 2011.

[6] P. G. Lejeune Dirichlet, “Sur une nouvelle méthode pour la détermination des intégrales multiples,” Journal de Mathématiques Pures et Appliquées, Série 1, Tome 4, 1839, pp. 164–168.

[7] F. W. J. Olver, A. B. Olde Daalhuis, D. W. Lozier, B. I. Schneider, R. F. Boisvert, C. W. Clark, B. R. Miller, B. V. Saunders, H. S. Cohl, and M. A. McClain, eds., NIST Digital Library of Mathematical Functions, Chapter 5: Gamma Function.

[8] C. F. Gauss, Disquisitiones generales circa superficies curvas, 1827.

[9] B. Riemann, Über die Hypothesen, welche der Geometrie zu Grunde liegen, 1854. English translation: On the Hypotheses which lie at the Bases of Geometry, translated by W. K. Clifford.

[10] G. Ricci-Curbastro and T. Levi-Civita, “Méthodes de calcul différentiel absolu et leurs applications,” Mathematische Annalen, 54 (1900), 125–201.

[11] É. Cartan, Leçons sur les invariants intégraux, Hermann, Paris, 1922.

[12] G. de Rham, Variétés différentiables, Hermann, Paris, 1955.

2025-04-06

comments

loading...

leave a note